Wesley Smith schrieb:
Hi,
I've overloaded the new, delete, new[] and delete[] operators in a C++
class defined as:
static void * operator new (size_t size);
static void operator delete (void *p);
static void * operator new[] (size_t size);
static void operator delete[] (void *p);
I've noticed if I do:
Object *o = new Object[100];
It calls new[] but if I do
delete o;
later it calls delete and therefore isn't symmetrical. How can I get
delete[] called?
Um... by calling it:
delete[] o;
It is part of the C++ language specification that arrays have to be
destroyed with operator delete[]. This comes from the syntactic ambiguity
between pointers and arrays. The compiler just cannot know if your o points
to a single element of type Object or an array of type Object, so we have
to tell him. If you use delete instead of delete[], only the first element
gets actually destructed (even though the memory of all elements is freed).
Daniel
