2007/7/27, Manish Baphna <manish_baphna@xxxxxxxxx>: > int number ; > > number = ( 0xFFFFFFFF >> 5 ) ; > cout << hex << number << endl ; > > number = ( ~0x0 >> 5 ) ; > cout << hex << number << endl ; > -------- > output >> 7ffffff > ffffffff > > Does that imply that '~' will always return a signed > value and hence this behavior ? Yes. '~' will return a signed number which can be printed as '-1'. 0xFFFFFFFF >> 5 depends on implementation. Because types of left and right operands are both floating-point number, gcc will parse them as unsigned integer. Hope to be helpful :) > Thanx in Advance :) > -Manish > > > > ____________________________________________________________________________________ > Sick sense of humor? Visit Yahoo! TV's > Comedy with an Edge to see what's on, when. > http://tv.yahoo.com/collections/222 > -- Best wishes! Yours, Lijuan Hai _ _ (_)(_) (,,) =()= ((__)\ _|L\_______/
