Hi Michael,
The type for the enum, as given, will be signed int.
Now if you want the enum to be ambiguous, you can do something like this:
enum { Uno = -1, Dos, Tres = 0x80000000 };
That will cause an ambiguous overload of the signed & unsigned assignment
operators, since the 0x80000000 will be taken to be an unsigned int as per
the standard C/C++ interpretation rules. (Assuming a 32-bit int platform.)
Is that the situation you are running into?
You can "fix" it by doing:
enum { Uno = -1, Dos, Tres = int(0x80000000) };
--Eljay
