chris@xxxxxxxxxxxxxxxxxxxx wrote:
I feel 10 is the correct answer due to the pre-increment operator having a higher precedence than the addition operator. This would mean both increments will be done before the addition (creating 5 + 5).
That's interesting. With b having been initialized to 3 but ending up at 5 on _both_ sides of "+" would imply that b was then incremented _four_ times (which is clarly not what the semantics of the statement are). I suspect a 10 to be the result of overly "smart" playing with the operands of the addition on the compiler's part: b is expected to be incremented twice as it must be evaluated twice according to the definition of the addition operation. However, the compiler also recognizes that the expression "++b" as operand to the "+" operator appears twice which it transforms into a multiplication of the addition's operand and 2. Remember also that addition is a commutative operation which means it is irrelevant in which order its operands are evaluated to produce the result. Cheers, Christian
