A C++ question

[Aseem Rastogi <aseem@xxxxxxxxxxxxxxxxxxxxxxx>]

Hi,

It is a C++ question and may not be applicable to this list. But, still 
if somebody can explain the behaviour. I have a small code as below:

class B
{
   public:
       int b;
       B () { b  = 0; };
       void foo2 (int h) { b = h; }
};

class A
{
   public:
       int a;
       A () { cout << "Inside default constructor" << endl; b = new B ();}

       B* b;

       void bar () const { b->foo2 (3); } // problem. how can this 
compile ?
};


void foo (const A* a)
{
   a->bar ();
}

int
main (int argc, char** argv)
{
   A a1;
   foo (&a1);
}

My concern is how could this code compile when in bar () function of 
class A, I am calling non const function on pointer b ?

If instead of pointer, b is an object of type B, I get correct error 
saying that inside const member function of class A, I cannot call non 
const member function of B.

Thanks in advance,

-Aseem.