function __attribute__ for non-external linkage?

[John Love-Jensen <eljay@xxxxxxxxx>]

Hi everyone,

Help!

If I have a Foo.cpp file with this...

static int Foo()
{
  return 0;
}

... I know that the Foo function has local linkage to the Foo.o translation
unit.

And that this...

namespace
{
int Foo()
{
  return 0;
}
}

... does *NOT* provide local linkage for Foo in the Foo.o translation unit,
rather Foo has external linkage.

(I presume D&E C++ covers why anonymous namespaces have external linkage,
but I don't recall off the top of my head, and I don't have D&E C++
available at the moment.  Probably something deep in the bowels of C++ which
makes it have that linkage by default.  Maybe RTTI related.  I don't know.)

Foo is name-mangled in a (hopefully) unique manner to make it effectively
non-linkable outside of the translation unit.

I can get the benefits of both facilities and do...

namespace
{
static int Foo()
{
  return 0;
}
}

So far so good.  So here's my problem:  how can I get local linkage to a
translation unit of a class's methods?

namespace
{
class Bar
{
public:
  void Quux(); // <-- how to make this have non-external/local linkage?
};
}

I don't want module linkage, I want translation unit local linkage.

I presume it's some sort of __attribute__ tag, maybe
__attribute((visibility("SomethingGoesHere")))?

Thanks,
--Eljay