Ian Lance Taylor wrote: > > This is a generic C question, not a question specific to gcc. > > The reason is that when arrays are passed as parameters, they decay to > pointers. The effect is that the const qualifer does not work as you > expect it to. Thanks for the replies, you are right the function is being treated something like: void test(int (*a)[1]) What's slightly strange is that if I make the array in main() const it compiles without the warning. Obviously removing the const in the test() argument is ok, it's a pity you can't mark a multi-dimensional array parameter as const, it's just part of the leagacy of C's pointer/array loose definition. Jon
