Re: trying to understand: "warning: function declaration isn't a prototype"

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Jay Vaughan <jv@xxxxxxxxxxxxxxx> writes:

> >The warning means that the code does something like this:
> >     extern int foo ();
> >The warning message will include a file name and line number you can
> >use to see where this is happening.
> >
> 
> yes, i understand this - i do not want to ignore this warning, i want
> to understand why the warning is emitted in the first place ..

Well, I explained why the warning is being emitted.

Perhaps you could rephrase your question.  Or perhaps you could
provide the exact error message and the line in the source code to
which it refers.

Ian

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