Re: trying to understand: "warning: function declaration isn't a prototype"

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The warning means that the code does something like this:
    extern int foo ();
The warning message will include a file name and line number you can
use to see where this is happening.


yes, i understand this - i do not want to ignore this warning, i want to understand why the warning is emitted in the first place ..


--

;

Jay Vaughan


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