Thomas,
Would this not work for you?
struct A
{
const A* a;
};
template <const char* c>
struct B
{
static const A b;
};
extern const char c[1]="";
extern const char d[1]="";
template<> const A B<d>::b;
template<> const A B<c>::b;
template<>
const A B<c>::b =
{
&B<d>::b
};
template<>
const A B<d>::b =
{
&B<c>::b
};
corey
On 7/7/05, Thomas Neumann <tneumann@xxxxxxxxxxxxxxxxxxxxx> wrote:
> Hi,
>
>
> > If a template, a member template or the member of a class template is
> > explicitly specialized then that specialization
> > shall be declared before the first use of that specialization that
> but how would I do this? For functions this is easy, but I don't think I
> can declare a static member variable without defining it at the same
> time. I tried some combinations (using extern etc.), but always got
> compiler errors.
>
> Thomas
>
