> we know rodata section have been relocated. > There have 24 bytes (6*4) modified. > > But as we know, relocation doesn’t tell how much byte will be modified, > why linker know six words will be relocated, I quite don't understand your question, but anyways see if this makes sense to you. The linker does not know 6 words are relocated. The linker only knows that there are 6 relocations to be performed. The information about how many bytes will be modified is decided by the linker based on the relocation type. The semantics of each of these operations are decided by the linker as specified in the processor specific ABI document. For example in the above case you mentioned a R_MIPS_HI16 and a R_MIPS_LO_16. Now the relocation is to .rodata + <some_addend> . The semantics of doing a R_MIPS_HI16 reloc is to calculate the address for the symbol being relocated which in this case is .rodata+some_addend and then take the top 16 bits and insert the value back into the text section where this needs to be used . Hope this answers your question. cheers Ramana > this is my question. > >
