In section 5.3.1 paragraph 1 and paragraph 3 of the C++ spec, I believe you'll find the reason for that error: Paragraph 1: The unary * operator performs indirection: the expression to which it is applied shall be a pointer to an object type, or a pointer to a function type and the result is an lvalue referring to the object or function to which the expression points. If the type of the expression is "pointer to T," the type of the result is "T." [Note: a pointer to an incomplete type (other than cv void ) can be dereferenced. The lvalue thus obtained can be used in limited ways (to initialize a reference, for example); this lvalue must not be converted to an rvalue, see 4.1. ] Paragraph 3: A pointer to member is only formed when an explicit & is used and its operand is a qualified-id not enclosed in parentheses. [Note: that is, the expression &(qualified-id), where the qualified-id is enclosed in parentheses, does not form an expression of type "pointer to member." Neither does qualified-id, because there is no implicit conversion from a qualified-id for a nonstatic member function to the type "pointer to member function" as there is from an lvalue of function type to the type "pointer to function" (4.3). Nor is &unqualified-id a pointer to member, even within the scope of the unqualified-id's class. ] corey On 5/24/05, Eljay Love-Jensen <eljay@xxxxxxxxx> wrote: > Hi Rune, > > func is a data member of the testfnptr object. > > Change this... > if (0 != (this->*func)) > ...to this... > if (0 != func) > > HTH, > --Eljay > >
