Okay, I did s,MY_API class,class MY_API. Now, when using colorgcc, I even saw
the warning you hinted me :)
However, when playing a bit around, I see, that I've to explicitely do:
template<class T>
void FOO_API TFoo<T>::bar(const T& var) {
std::cout << "TFoo::bar(" << var << ")" << std::endl;
}
no you don't.
I don't know what's wrong with your example but the following works:
test.h:
template<typename T>
struct API A{
void f();
};
test.cpp: -fvisibility=hidden -shared
#define API __attribute__((visibility("default")))
#include "test.h"
template<typename T>
void A<T>::f(){}
template class A<int>;
test2.cpp: -ltest
#define API
#include "test.h"
int main(){
A<int> a;
a.f();
}
--
Stefan Strasser
