This means that you basically need to know what these types are and what can and can't be auto converted.
In your case, you are treating a *char as an int.
If you are using C++, the most eligant way to do this is via boost::lexical_cast. In C, there are more primative facilities. Look for atoi documentation.
Larry Brown wrote:
I hope I'm in the right place... I am a fairly accomplished php developer and have written quite a bit of code with it. However, all of my coding experience has been with scripting languages and I have never had to deal with memory allocation and rarely ever dealt with pointers or casting etc.
For instance...
with scripting I can simply access arguments by referencing the string at argv[1] or ARGV[1] etc. It looks like I should be able to do this with c but I have to reference *argv[x] and *argv[x] only holds the first character. The following is a snippet...
int main(int argc, *argv[]) { int secondVar=*argv[2]; }
if the second argument is say ... 10, I only get the 1. There is some logic that I must follow that I can't see. I've tried looking at *argv[2][0] to see if it was one and *argv[2][1] was zero but is aparently not the case.
I have looked at several howto/instruction documents and none seem to
yeild much.
TIA
Again, I hope I'm in the right place...
Larry
