> On 2019-11-25 14:55, Milan Broz wrote: Hi Milan, just to make sure there is no misunderstanding: > Then there is alignment, so the real data offset is aligned by default to > the 1MB boundary. > > With this padding, header size is for 128bit key 2MB, for 256/512 key 4MB. I am actually using 512 bit key: --cipher aes-xts-plain64 --key-size 512 --hash sha512 so it would seem I need 4MB header for luks1 with 512 key > Yes. For reference: for 128bit it is 528384 bytes, for 256bit 1052672 > bytes, > for 512bit (2x256bits in XTS mode) it is 2068480 bytes. now I am confused. 2068480 is less than 2MB. So when aligned to 1MB boundary, 2MB would be enough for luks1 with 512 key. So is it 2MB or 4MB ? many thanks, _______________________________________________ dm-crypt mailing list dm-crypt@xxxxxxxx https://www.saout.de/mailman/listinfo/dm-crypt
