Hi, the block size is always 512 bytes for cryptsetup. The tweak is, I think, the block-number as counted from the offset. You can read the key and offset as described in FAQ Item 6.10. Regards, Arno On Fri, Jun 10, 2016 at 17:02:52 CEST, jonetsu wrote: > I would like to determine the block size that's used with aes-xts-plain64 as well as the tweak value. The file system is ext2 and the information returned by parted is: > > Model: Linux device-mapper (linear) (dm) > Disk /dev/mapper/luksvg-confd: 21.0MB > Sector size (logical/physical): 512B/512B > Partition Table: loop > > Number Start End Size File system Flags > 1 0.00B 21.0MB 21.0MB ext2 > > The command used is: > > cat /root/cryptkey | cryptsetup luksFormat /var/lib/luksfile --key-file - --cipher aes-xts-plain64 \ > --key-size 256 --hash sha512 -i 5000 --align-payload 2048 > > How can the value of the block size and the tweak value ne known ? > > Thanks. > > > > _______________________________________________ > dm-crypt mailing list > dm-crypt@xxxxxxxx > http://www.saout.de/mailman/listinfo/dm-crypt -- Arno Wagner, Dr. sc. techn., Dipl. Inform., Email: arno@xxxxxxxxxxx GnuPG: ID: CB5D9718 FP: 12D6 C03B 1B30 33BB 13CF B774 E35C 5FA1 CB5D 9718 ---- A good decision is based on knowledge and not on numbers. -- Plato If it's in the news, don't worry about it. The very definition of "news" is "something that hardly ever happens." -- Bruce Schneier _______________________________________________ dm-crypt mailing list dm-crypt@xxxxxxxx http://www.saout.de/mailman/listinfo/dm-crypt
