I would like to determine the block size that's used with aes-xts-plain64 as well as the tweak value. The file system is ext2 and the information returned by parted is: Model: Linux device-mapper (linear) (dm) Disk /dev/mapper/luksvg-confd: 21.0MB Sector size (logical/physical): 512B/512B Partition Table: loop Number Start End Size File system Flags 1 0.00B 21.0MB 21.0MB ext2 The command used is: cat /root/cryptkey | cryptsetup luksFormat /var/lib/luksfile --key-file - --cipher aes-xts-plain64 \ --key-size 256 --hash sha512 -i 5000 --align-payload 2048 How can the value of the block size and the tweak value ne known ? Thanks. _______________________________________________ dm-crypt mailing list dm-crypt@xxxxxxxx http://www.saout.de/mailman/listinfo/dm-crypt
