On Sun, 2010-07-25 at 17:32 +0200, Arno Wagner wrote: > 512B * 2 ^64 = 9444 EB = 9.2 * 10^21 B btw: the 512 bytes... is this always the statical block size in cryptsetup/dm-crypt or would I have to use e.g. 4K if I have a disk with such a block size (i.e. does cryptsetup/dm-crytp always use 512b blocks or does it use the underlying physical block size)? Thanks, Chris.
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