On Tue, Dec 19 2023 at 03:15, James Tai [戴志峰] wrote:
>>On Wed, Nov 29 2023 at 13:43, James Tai wrote:
>>> +static inline void realtek_intc_clear_ints_bit(struct
>>> +realtek_intc_data *data, int bit) {
>>> + writel(BIT(bit) & ~1, data->base + data->info->isr_offset);
>>
>>That '& ~1' solves what aside of preventing bit 0 from being written?
>>
> The ISR register uses bit 0 to clear or set ISR status.
> Write 0 to clear bits and write 1 to set bits.
> Therefore, to clear the interrupt status, bit 0 should consistently be
> set to '0'.
And how does BIT(bit) with 1 <= bit <= 31 end up having bit 0 set?
Also a comment explaining the reasoning here would be helpful.
