The aggregation over votes for all nodes in the provider will always
only find the bandwidth votes for the destination side of the path.
Further more, the average kBps value will always be 0.
Simplify the logic by directly looking at the destination node's peak
bandwidth request.
Signed-off-by: Bjorn Andersson <quic_bjorande@xxxxxxxxxxx>
Tested-by: Steev Klimaszewski <steev@xxxxxxxx>
---
Changes since v1:
- None
drivers/interconnect/qcom/osm-l3.c | 10 +---------
1 file changed, 1 insertion(+), 9 deletions(-)
diff --git a/drivers/interconnect/qcom/osm-l3.c b/drivers/interconnect/qcom/osm-l3.c
index 469be732a00b..5fa171087425 100644
--- a/drivers/interconnect/qcom/osm-l3.c
+++ b/drivers/interconnect/qcom/osm-l3.c
@@ -134,22 +134,14 @@ static int qcom_osm_l3_set(struct icc_node *src, struct icc_node *dst)
struct qcom_osm_l3_icc_provider *qp;
struct icc_provider *provider;
const struct qcom_osm_l3_node *qn;
- struct icc_node *n;
unsigned int index;
- u32 agg_peak = 0;
- u32 agg_avg = 0;
u64 rate;
qn = src->data;
provider = src->provider;
qp = to_osm_l3_provider(provider);
- list_for_each_entry(n, &provider->nodes, node_list)
- provider->aggregate(n, 0, n->avg_bw, n->peak_bw,
- &agg_avg, &agg_peak);
-
- rate = max(agg_avg, agg_peak);
- rate = icc_units_to_bps(rate);
+ rate = icc_units_to_bps(dst->peak_bw);
do_div(rate, qn->buswidth);
for (index = 0; index < qp->max_state - 1; index++) {
--
2.17.1
