Hi, On 12/12/16 15:05, Bartosz Golaszewski wrote: > +&lcdc { > + status = "okay"; > + pinctrl-names = "default"; > + pinctrl-0 = <&lcd_pins>; > + > + ports { > + #address-cells = <1>; > + #size-cells = <0>; > + > + lcdc_out: port@1 { > + #address-cells = <1>; > + #size-cells = <0>; > + reg = <1>; > + > + lcdc_out_vga: endpoint { > + reg = <0>; > + remote-endpoint = <&vga_bridge_in>; > + }; > + }; > + }; > +}; > This is not correct. LCDC has just one output, so port@1 doesn't make sense. It's port@0. But with just one port, you can leave "ports" away. And you don't need the port's label for anything, if I'm not mistaken. So: &lcdc { status = "okay"; pinctrl-names = "default"; pinctrl-0 = <&lcd_pins>; port { lcdc_out_vga: endpoint { remote-endpoint = <&vga_bridge_in>; }; }; }; Tomi
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