On 21/11/10 14:41, Jilles Tjoelker wrote:
The backslash prevents the closing brace from terminating the
substitution, therefore it should be removed.
Thanks, that works great.
Example:
printf "%s\n" ${$+\}} ${$+"\}"} "${$+\}}"
should print } three times, without backslashes.
Some tests with different a few shells:
"${$+'\}'}"
"${$+"\}"}"
"${$+\}}"
${$+'\}'}
${$+"\}"}
${$+\}}
bash | } \} \} \} } '\}'
pdksh | } \} \} } \} \}
ksh | } } \} } } '}'
dash (current) | } \} \} \} \} '\}'
dash (patched) | } } \} } } '}'
The one thing that I was a bit confused about was the difference between
${$+'\}'} and ${$+"\}"}, but I do think that is correct: the backslash
is used to see that the immediately following } is not a terminator, but
the special rule allowing backslash before } to be removed in
double-quoted strings in parameter expansions does not apply (there is
no double-quoted string), so the backslash appears in the output as
well. And since the last form uses a double-quoted string, the backslash
gets removed there.
Cheers,
Harald
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