This isn't a drop-in replacement for strlen(). It works differently
for strings with \0 buried somewhere in the middle.
Regards,
Radek
On Wed, Jun 14, 2017 at 7:16 PM, Michal Jarzabek <stiopa@xxxxxxxxx> wrote:
> You could also do :
>
> template< size_t N >
> constexpr size_t string_length(const char (&)[N] )
> {
> return N-1;
> }
>
>
> On Wed, Jun 14, 2017 at 5:50 PM, Jesse Williamson <jwilliamson@xxxxxxx> wrote:
>>
>>
>> Here's a C++11 version that might be useful to you (largely untested,
>> and I'm only on my first cup of coffee, so... ;>).
>>
>> -Jesse
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