Re: Inquiry:How to compare two files but not in line-by-line basis?

[mark <m.roth@xxxxxxxxx>]

hadi motamedi wrote:
> On Thu, Dec 3, 2009 at 12:42 PM, mark <m.roth@xxxxxxxxx> wrote:
> 
>> John Doe wrote:
>>> From: hadi motamedi <motamedi24@xxxxxxxxx>
>>>> Can you please do me favor and let me know if I can go further and try
>> for
>>>> advanced search like finding how many rows inside a file have data that
>>>> does not start with a zero after the third comma ?
>>> Something like: awk -F, ' { print $4 } ' | grep -v "^0" | wc -l Use one
>>> command at a time to see how they work with each other (you might have to
>>> modify the grep a bit)...
>> *sigh*
>>
>> Drive me crazy, why use multiple commands?
>>
>> awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print
>> count }'
>> filename
> 
> Sorry . I tried for your proposed procedure , as the followings :
> #awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print
> count }' HLRSubscriber-20091111173349.csv
> But my CentOS server didn't return to the prompt . Can you please let me
> know why it is in an end-less iterated loop ?
> Thank you in advance

Syntax error. You wrote
if ( $3 !~ /^0
not
if ( $3 !~ /^0/

PLEASE: if you ask for help, and someone gives you examples, READ THE MAN PAGES 
SO THAT YOU KNOW WHAT YOU'RE DOING. I could have just as well have given you 
something that would have wiped your system (like system("rm -rf /").

	mark
-- 
America is the only country that went from barbarism to
decadence without civilization in between.
   - Oscar Wilde
_______________________________________________
CentOS mailing list
CentOS@xxxxxxxxxx
http://lists.centos.org/mailman/listinfo/centos