On Thu, Dec 3, 2009 at 12:42 PM, mark <m.roth@xxxxxxxxx> wrote:
John Doe wrote:*sigh*
> From: hadi motamedi <motamedi24@xxxxxxxxx>
>> Can you please do me favor and let me know if I can go further and try for
>> advanced search like finding how many rows inside a file have data that
>> does not start with a zero after the third comma ?
>
> Something like: awk -F, ' { print $4 } ' | grep -v "^0" | wc -l Use one
> command at a time to see how they work with each other (you might have to
> modify the grep a bit)...
Drive me crazy, why use multiple commands?
awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print count }'
filename
mark "why, yes, since you ask, I *have* written 100 and
200 line awk scripts"
--
Though I don't think (object-oriented programming) has much to offer good
programmers, except in certain specialized domains, it is irresistible to
large organizations. Object-oriented programming offers a sustainable way
to write spaghetti code. - Paul Graham
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Sorry . I tried for your proposed procedure , as the followings :
#awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print count }' HLRSubscriber-20091111173349.csv
But my CentOS server didn't return to the prompt . Can you please let me know why it is in an end-less iterated loop ?
Thank you in advance
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