On Tue, Apr 21, 2009 at 9:09 PM, Per Qvindesland <per@xxxxxxxxxx> wrote: > > I am hoping that someone here could perhaps give me a straight answer on a > question that someone asked me today > I have always belived that if you have 5 hard drives 1 50gb second 50gb > third 20gb fourth 60gb firth 30gb that the largest would then be the size of > the smallest disk, not 80 or 100 or 120 for that matter or am I wrong here? In your example the smallest disk is 20gb, this will limit the size of the array. This means that the size of the array would be 20 * (5-1) = 80gb. Regards, Tim -- Tim Verhoeven - tim.verhoeven.be@xxxxxxxxx - 0479 / 88 11 83 Hoping the problem magically goes away by ignoring it is the "microsoft approach to programming" and should never be allowed. (Linus Torvalds) _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos