Hello all,
I am trying to configure a subdomain DNS server on a Cent OS 5.1 - for
my lab. Brief configuration:
Lab machine ---> 192.168.17.2 (should respond to DNS queries from
hosts in 192.168.16.0/20 network)
1. I would also like to forward any queries outside the above network
to our corporate domain (no firewalls between our 192.168.16.x network
and the corporate network. The domain server is: dns.company.com
with an IP of 10.100.1.2 (255.255.255.0).
2. What I have configured is:
192.168.17.2 --> myhost.lab.company.com
10.100.1.2 --> dns.company.com
3. Installed the dns bind 9 in myhost and set basic configuration via
the system-config-bind GUI. My configuration file specific to my
setup there is:
cat lab.maxiscale.com.db
$TTL 1H
@ SOA myhost.lab.company.com.
root.myhost.lab.company.com. ( 2
3H
1H
1W
1H )
NS myhost.lab.company.com.
qaserver2 A 192.168.17.3
qaserver1 A 192.168.17.1
myhost A 192.168.17.2
=================
The rest of the DNS/Bind records were based upon the auto-generated
files from the Bind GUI Config tool.
3. I also changed myhost's resolv.conf to reflect the following:
search lab.mycompany.com
192.168.17.2
search mycompany.com
10.100.1.2
======
PROBLEM:
1. When I am in myhost.com, I can perform:
a. nslookup hostname (to any host within 192.168.x and 10.100.x networks)
b. nslookup ip to anyhost wtihin both networks.
2. When I am in one of the hosts within 192.168.x aside from
myhost.com (for example, qaserver1 or qaserver2):
a: SUCCESS to nslookup hostname to any host within BOTH networks.
b. FAILS to nslookup ip (reverse nslookup) to anyhost within the
10.100.x network.
this is the error I get:
nslookup 10.100.1.2
Server: 192.168.17.2
Address: 192.168.17.2#53
Non-authoritative answer:
24.1.100.10.in-addr.arpa name = dns.company.com.
Authoritative answers can be found from:
. nameserver = e.root-servers.net.
. nameserver = f.root-servers.net.
. nameserver = g.root-servers.net.
. nameserver = h.root-servers.net.
. nameserver = i.root-servers.net.
. nameserver = j.root-servers.net.
. nameserver = k.root-servers.net.
. nameserver = l.root-servers.net.
. nameserver = m.root-servers.net.
. nameserver = a.root-servers.net.
. nameserver = b.root-servers.net.
. nameserver = c.root-servers.net.
. nameserver = d.root-servers.net.
a.root-servers.net internet address = 198.41.0.4
b.root-servers.net internet address = 192.228.79.201
c.root-servers.net internet address = 192.33.4.12
d.root-servers.net internet address = 128.8.10.90
e.root-servers.net internet address = 192.203.230.10
f.root-servers.net internet address = 192.5.5.241
g.root-servers.net internet address = 192.112.36.4
h.root-servers.net internet address = 128.63.2.53
i.root-servers.net internet address = 192.36.148.17
j.root-servers.net internet address = 192.58.128.30
k.root-servers.net internet address = 193.0.14.129
k.root-servers.net has AAAA address 2001:7fd::1
l.root-servers.net internet address = 199.7.83.42
=====
I must be missing something stupid and apparent .... any help would be
greatly appreciated!!!
:)
thanks in advance!
--
best,
Vince
_______________________________________________
CentOS mailing list
CentOS@xxxxxxxxxx
http://lists.centos.org/mailman/listinfo/centos
