On Tue, Aug 28, 2007 at 10:13:00AM -0400, Scott McClanahan wrote:
> On Tue, 2007-08-28 at 10:08 -0400, Stephen Harris wrote:
> > > Not a CentOS specific question, although I am running grep on CentOS 4.3
> > > but how would you grep out a series of lines in a file starting at a
> > > specific point. For instance, if I have a file named foo and I want to
> > > grep out the next 5 lines after the first and only instance of the
> > > string "bar" how could I pull that off? Thanks so much.
> >
> > What do you mean by "grep out" ? Do you want to display those lines,
> > or skip those lines? Do you want to see the "bar" line? Is that included
> > in the 5 lines?
> >
> > Anyway, you probably want to use "sed" here, rather than "grep".
> >
> I'd like to skip those lines. I'd like to skip the line with "bar" and
> the following five lines.
Like this?
$ cat xx
line 1
line 2
line bar
line after 1
line after 2
line after 3
line after 4
line after 5
line after 6
line after 7
$ sed '/bar/,+5d' xx
line 1
line 2
line after 6
line after 7
--
rgds
Stephen
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