> Not a CentOS specific question, although I am running grep on CentOS 4.3
> but how would you grep out a series of lines in a file starting at a
> specific point. For instance, if I have a file named foo and I want to
> grep out the next 5 lines after the first and only instance of the
> string "bar" how could I pull that off? Thanks so much.
What do you mean by "grep out" ? Do you want to display those lines,
or skip those lines? Do you want to see the "bar" line? Is that included
in the 5 lines?
Anyway, you probably want to use "sed" here, rather than "grep".
--
rgds
Stephen
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