On Tue, Mar 22, 2005 at 12:21:18PM -0000, liquid@xxxxxxxxxxxxxx wrote: > Start Python and type (of course x.x.x.x should be replaced with > IP address): > > import socket > s=socket.socket(socket.AF_INET,socket.SOCK_RAW,4) > s.sendto("",("x.x.x.x",0)) > > Press ENTER and your win box should crash immediately. I tested this on WinXP SP2 with Python 2.4. The result is an exception: socket.error: (10022, 'Invalid argument') I don't have Python 2.3 installed otherwise I would test that too. Neil