Wouldn't for do it some how? The little I knew about hyperlogo, one would think of something like for numbers=1-99 cat file.a$numbers > file At 02:50 AM 12/7/01 -0500, you wrote: >That's exactly what the awk command I posted (using eval), and the xargs >commands posted by others, do; without the extra steps. > >On Fri, 7 Dec 2001, Jude DaShiell wrote: > >> Your safest way is going to be with a little shell script. If you have >> the vis command it's probably better than cat -v. I don't know if these >> files are parts of a binary or text file. The general script would look >> something like this. The redirection I do is for a good reason. cat -v a1 >> a2 a3 a4 a5 a6 a7 a8 a9 >>afile. The first line of the script would be >> #!/bin/sh. That longer line I wrote earlier would be duplicated as many >> times as necessary and you'd change the numbers each line down the script. >> so that the last line in the script would be cat a91 a92 a93 a94 a95 a96 >> a97 a98 a99 >>afile. If you use a command like .,.s/a[1-9]/a1[1-9]/gp >> <cr> That should change line 3 in the script from cat a1 a2 a3 a4 to cat >> a11 a12 a13 a14 etc. >> >> Jude <jdashiel@shellworld.net> >> >> >> >> >> _______________________________________________ >> >> Blinux-list@redhat.com >> https://listman.redhat.com/mailman/listinfo/blinux-list >> > > > >_______________________________________________ > >Blinux-list@redhat.com >https://listman.redhat.com/mailman/listinfo/blinux-list > >