On 2/25/20 11:52 AM, Christian König wrote:
Am 25.02.20 um 11:39 schrieb Nirmoy Das:
changing ring->sched.ready should be done only if the ring is
initialized
I don't think that this makes much difference. When the rings are
freed the hardware and software stack needs to be disabled quite some
time before.
Yes it doesn't make any difference. I wanted amdgpu_ring_fini() to look
bit cleaner.
Regards,
Nirmoy
Christian.
Signed-off-by: Nirmoy Das <nirmoy.das@xxxxxxx>
---
drivers/gpu/drm/amd/amdgpu/amdgpu_ring.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/drivers/gpu/drm/amd/amdgpu/amdgpu_ring.c
b/drivers/gpu/drm/amd/amdgpu/amdgpu_ring.c
index 539be138260e..18e11b0fdc3e 100644
--- a/drivers/gpu/drm/amd/amdgpu/amdgpu_ring.c
+++ b/drivers/gpu/drm/amd/amdgpu/amdgpu_ring.c
@@ -344,12 +344,13 @@ int amdgpu_ring_init(struct amdgpu_device
*adev, struct amdgpu_ring *ring,
*/
void amdgpu_ring_fini(struct amdgpu_ring *ring)
{
- ring->sched.ready = false;
/* Not to finish a ring which is not initialized */
if (!(ring->adev) || !(ring->adev->rings[ring->idx]))
return;
+ ring->sched.ready = false;
+
amdgpu_device_wb_free(ring->adev, ring->rptr_offs);
amdgpu_device_wb_free(ring->adev, ring->wptr_offs);
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