Tks takashi....
The doubt comes from this block of code:
for (chn = 0; chn < channels; chn++) {
if ((areas[chn].first % 8) != 0) {
printf("areas[%i].first == %i, abortando...\n", chn,
areas[chn].first);
exit(EXIT_FAILURE);
}
//pega endereço e offset da area
samples[chn] = /*(signed short *)*/(((unsigned char
*)areas[chn].addr) + (areas[chn].first / 8));
if ((areas[chn].step % 16) != 0) {
printf("areas[%i].step == %i, aborting...\n", chn,
areas[chn].step);
exit(EXIT_FAILURE);
}
steps[chn] = areas[chn].step / 8;
samples[chn] += offset * steps[chn];
}
first:
areas[chn].first % 8 ( I am using chn = 1). So for the only area that
I have, if I get the value of the parameter 'first' isn't divisible by
8, the program exits.
The same doubt happens with "areas[chn].step % 16" and
"areas[chn].step / 8".
This is the parameter I am using:
static snd_pcm_format_t format = SND_PCM_FORMAT_S16; //sample format
unsigned 16 bit endian
Perhaps with this practical example I can understand better.
Thanks for ur patient!
Tks!
-------------------
Guilherme Longo
Dept. Eng. da Computação
Unaerp
Linux User - #484927
*Before Asking
http://www.istf.com.br/?page=perguntas
!- I'd rather die on my feet than live on my knees -!
Takashi Iwai wrote:
> At Fri, 26 Jun 2009 23:56:43 -0300,
> Guilherme wrote:
>
>> Takashi...
>>
>> The base_address and the step sounds pretty clear to me.... just the
>> offset I could not understand.
>>
>> What the difference in being .first = 0 or .first = 2??? Could you
>> provide please a more in depth explanation. I tried really hard find
>> this but there is nothing related in the documentation.
>>
>> area[0].addr = base_address;
>> addr[0].first = 0;
>> addr[0].step = 4;
>> addr[1].addr = base_address;
>> addr[1].first = 2;
>> addr[1].step = 4;
>>
>> P.S. being a stereo or a mono pipeline I understand... just the way the offset works that is not so clear to me.
>>
>
> Actually, the non-interleaved formats can be represented also with
> a single base_address (and is so in the actual implementation).
>
> addr[0].addr = base_addr;
> addr[0].first = 0;
> addr[0].step = 2;
> addr[1].addr = base_addr;
> addr[1].first = mono_buffer_len;
> addr[1].step = 2;
> addr[2].addr = base_addr;
> addr[2].first = mono_buffer_len * 2;
> addr[2].step = 2;
> ...
>
> The "first" is the offset of the first sample. The address of the
> first sample of the channel is simply calculated as addr + first.
> This is because just we want to keep the base address same to all
> channels as much as possible especially in mmap mode.
>
>
> Takashi
>
>
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