Despite what the data sheet says in one place, to get stereo input
from input A (line in), we have to clear the "input B monaural" bit in
the ACR.
Signed-off-by: Paul Mackerras <paulus@xxxxxxxxx>
---
diff --git a/sound/aoa/codecs/snd-aoa-codec-tas.c b/sound/aoa/codecs/snd-aoa-codec-tas.c
index 2ef55a1..9de8485 100644
--- a/sound/aoa/codecs/snd-aoa-codec-tas.c
+++ b/sound/aoa/codecs/snd-aoa-codec-tas.c
@@ -514,9 +514,15 @@ static int tas_snd_capture_source_put(st
mutex_lock(&tas->mtx);
oldacr = tas->acr;
- tas->acr &= ~TAS_ACR_INPUT_B;
+ /*
+ * Despite what the data sheet says in one place, the
+ * TAS_ACR_B_MONAUREAL bit forces mono output even when
+ * input A (line in) is selected.
+ */
+ tas->acr &= ~(TAS_ACR_INPUT_B | TAS_ACR_B_MONAUREAL);
if (ucontrol->value.enumerated.item[0])
- tas->acr |= TAS_ACR_INPUT_B;
+ tas->acr |= TAS_ACR_INPUT_B | TAS_ACR_B_MONAUREAL |
+ TAS_ACR_B_MON_SEL_RIGHT;
if (oldacr == tas->acr) {
mutex_unlock(&tas->mtx);
return 0;
@@ -686,8 +692,7 @@ static int tas_reset_init(struct tas *ta
if (tas_write_reg(tas, TAS_REG_MCS, 1, &tmp))
goto outerr;
- tas->acr |= TAS_ACR_ANALOG_PDOWN | TAS_ACR_B_MONAUREAL |
- TAS_ACR_B_MON_SEL_RIGHT;
+ tas->acr |= TAS_ACR_ANALOG_PDOWN;
if (tas_write_reg(tas, TAS_REG_ACR, 1, &tas->acr))
goto outerr;
-------------------------------------------------------------------------
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