[Yum] Calling yum from python

[chandan-dutta.chowdhury at hp.com (Chowdhury, Chandan Dutta (STSD))]

Hello All,

I am trying to call yum from python. 
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Following is the way I try to this [code-1]
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#!/usr/bin/env python

import sys

sys.path.insert(0, "/usr/share/yum-cli")
import yummain
yummain.main("search bash".split())
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But all I get is the usage message
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You need to give some command

usage: yum [options] < update | install | info | remove | list |
    clean | provides | search | check-update | groupinstall |
    groupupdate | grouplist | groupinfo | groupremove |
    makecache | localinstall | erase | upgrade | whatprovides |
    localupdate | resolvedep | shell | deplist >

options:
  -h, --help            show this help message and exit
  -t, --tolerant        be tolerant of errors
  -C                    run entirely from cache, don't update cache
....
...
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If I try this instead [code-2]
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#!/usr/bin/env python

import sys

sys.path.insert(0, "/usr/share/yum-cli")
import yummain

sys.argv=sys.argv + "search bash".split()
yummain.main(sys.argv[1:])
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It works without any problem

Code-1 works with 2.2.2 and not with 2.4.3 or 2.9.0 (I get the usage
message). I think yummain uses sys.argv instead of using the list
passed.
Code-1 works with all the version, but I don't want to set or change the
argv. 

The objective is to get the functionality of yum from python code

Thanks for any help

Regards
Chandan Dutta Chowdhury