On 12/21/2010 02:05 PM, Callahan, Tom wrote: > The trick is, 6123716 KB isn't actually 6GB, it's slightly less. That's why > you are getting the results you are getting. > > http://www.google.com/search?q=6123716KB+in+GB > > > On 12/21/10 7:18 AM, "Patrick Lists" <ks-list@xxxxxxxxxxxxxxxxx> wrote: > >> 6123716 Yup see that now. Still I wonder why free says MemTotal is less than 6GB when the box has 6GB. That's the interesting part. I seem to be missing something. Where did those last few bytes go? Or could this be a case of GB versus GiB. Strangely this awk line does work but I have no awk foo so this is like dark arts to me (line 2,3,4 should all be on one line): mem=$(free|grep Mem|awk '{print$2}') echo "$mem" | awk '{ n = $0; sub(/[0-9]+(.[0-9]+)?/, ""); split(n, a, $0); n=a[1]; if ($0 == "G" || $0 == "") { n *= 1024 }; if (/^kB?/) { n /= 1024 }; printf "%d\n", n }' # Intentionally rounded to an integer Regards, Patrick _______________________________________________ Kickstart-list mailing list Kickstart-list@xxxxxxxxxx https://www.redhat.com/mailman/listinfo/kickstart-list
