On 07/13/2016 08:46 PM, Chris Adams wrote:
Once upon a time, Jon LaBadie <jonfu@xxxxxxxxxx> said:
On Thu, Jul 14, 2016 at 02:09:27AM +0000, Christopher wrote:
On Wed, Jul 13, 2016, 21:11 Chris Adams <linux@xxxxxxxxxxx> wrote:
Once upon a time, Mike Wright <nobody@xxxxxxxxxxxxxxxxxxxx> said:
Putting all that together, I'd recommend:
PATTERN='https?://[^/]*\.in/'
grep "$PATTERN" file.of.links > links.in
Minor nit, egrep is needed for the '?' or grep -E.
Oops, yep. I'm usually writing perl (and occasionally using grep -P) so
I forgot.
OK, thanks everybody.
Had to use egrep. This works:
PATTERN='https?://[^/]*\.in(/.*)*'
egrep $PATTERN file.of.links > links.in
Covers cases with https and where nothing follows the .in
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