On Wed, Jul 13, 2016, 21:11 Chris Adams <linux@xxxxxxxxxxx> wrote:
Once upon a time, Mike Wright <nobody@xxxxxxxxxxxxxxxxxxxx> said:
Putting all that together, I'd recommend:
PATTERN='https?://[^/]*\.in/'
grep "$PATTERN" file.of.links > links.in
or just:
grep 'https?://[^/]*\.in/' file.of.links > links.in
Only potential oddity would be if you have URLs with non-standard ports
specified (like "https://foo.in:8080/"); to match that, you could use
egrep instead (extended regex):
egrep 'https://[^/]*\.in(:[0-9]+)?/' file.of.links > links.in
One extra change I'd make, to make it more obvious you are checking for a literal dot and not intending to escape, use [.] instead of \.
So,
egrep 'https://[^/]*[.]in(:[0-9]+)?/' file.of.links > links.in
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