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M E Fieu wrote:
> Hi.. Need to ask you a simple script question, I used the date
> command to get the yesterday web log file using the following
> command echo ex`date -d yesterday +%y%m%d.log` in Linux. I want to
> create a simple script to cat /home/IT/ex060530.log> kr.log using
> the following script but it is not working. May I know how do I put
> the output of echo ex`date -d yesterday +%y%m%d.log into cat
> /home/IT/xxxx> kr.log ?
>
> [root@w2 krweblog3]# echo ex`date -d yesterday +%y%m%d.log`
> ex060530.log
>
> [root@w2 krweblog3]# vi krweblog.sh
>
> #!/bin/sh
> #
> KRWEBLOG3= echo ex`date -d yesterday +%y%m%d.log`
> cat /home/IT/$KRWEBLOG3> kr.log
Get rid of the echo, it's not needed.
KRWEBLOG3="ex`date -d yesterday +%y%m%d.log`
If you ever do have to run a few commands to create a variable, you
can use bash's command substitution to nest commands. Instead of
using backquotes (`command`), you use $(command).
KRWEBLOG3=$(echo ex$(date -d yesterday +%y%m%d.log))
See the section on Expansion in the bash man page for more details.
- --
Todd OpenPGP -> KeyID: 0xD654075A | URL: www.pobox.com/~tmz/pgp
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A free society is one where it is safe to be unpopular.
-- Adlai Stevenson
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