i'm increasingly puzzled here. i use a kensington expert mouse trackball on the which has four buttons, one on each corner. it is connected to the ps/2 port and is /dev/psaux. forever, xfree has mapped these buttons such that i have two left and two right buttons -- and i'm perfectly happy with this. but with my install of suse 9.1, which has an xfree that identifies itself as 4.3.99, i have one lmb -- lower left; one rmb -- lower right; nd two middle buttons -- both the top ones. the current xfree documentation lists a kensington protocol, but the xfree suse supplied is having none of it. to further cloudy matters, i am able to do the "DragLockButtons" option, such that the upper left becomes a locked lmb. this is of limited utility, in that i do not especially need a locked lmb and the corollary, a locked rmb, is entirely useless. ideally, i would have this setup: upper left=lmb; upper right=rmb; lower left=locked lmb; lower right=middle button. of all this, what is most important to me is upper left as left and upper right as right. according to the documentation, i should be able to achieve this by unoptioned ps/2 protocol. but, as i said, what i get with plain ps/2 is two middle mouse buttons. the appropriate section of xfree is this: Section "InputDevice" Driver "mouse" Identifier "Mouse[1]" Option "Device" "/dev/psaux" Option "Emulate3Buttons" Option "Protocol" "PS/2" Option "DragLockButtons" "2 1" it is identical to previous mouse sections of my XF86Config in which the button mapping was what i wanted, which is as documented: two left, two right. how do i recover that configuration? is some suse configurator doing me a "favor"? thanks for any help anyone can provide. -- dep _______________________________________________ XFree86 mailing list XFree86@xxxxxxxxxxx http://XFree86.Org/mailman/listinfo/xfree86
