Re: Date Problem

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Hi Toby, Jacob

Thank You Toby and Jacob for your help! I figured my way out and was able
to fix the issue, what i did was, i built another table called servicesdue
and updated the columns service1,service2,service3, used DATE_ADD to
populate these 3 date fields.

I figured the best way to go forward to have the new table with the
saledate and the service due dates, this way even while the system is
working, the calls to the DB and back to the page will be very less
expensive on the CPU, since PHP doesn't have to calculate a lot of things
and doesn't have to browse through the entire DB with these calculated
values.

This way the draw back is that there might be more memory usage since there
is a new table with data in it, but then the script only has to go through
the page once every day.

Correct me if my way of thinking on this was incorrect?

Thanks,
Vinay

On Thu, Jun 21, 2012 at 4:46 PM, Toby Hart Dyke <toby@xxxxxxxxxxxx> wrote:

> The date_add() function is your friend here. You will need to define what
> happens when the start date is something like Nov 30th. When is the first
> service due after that? If you use date_add() to add three months, it will
> return March 1st (in a non-leap year).
>
> Your first step should be to define the business rules - what happens when
> a
> date doesn't exist (like February 30th)? Is it OK if the returned date is
> on
> a weekend? Or a holiday?
>
>  Toby
>
>
> > -----Original Message-----
> > From: Vinay Kannan [mailto:vinykan@xxxxxxxxx]
> > Sent: Thursday, June 21, 2012 2:27 AM
> > To: php-windows@xxxxxxxxxxxxx; phpexperts@xxxxxxxxxxxxxxx; php mysql
> > Subject:  Date Problem
> >
> > Hey Guys,
> >
> > I am working on a project for a client who is a retailer of inverters and
> > batteries, and currently the system records the salesdetails including
> the
> > warranty expiry date which is always a year(12 months).
> >
> > But he wishes to provide support and service every 3 months and that
> seems
> > to be the beginning of my problems :D
> >
> > if the warranty on billno ='100' expires on 2012-09-27, the system has to
> show
> > him this billno 4 times as a service due.
> > Eg: a product was sold and a bill generated on 2011-9-27, the warranty on
> the
> > products expires on 2012-9-27, so the system has to show the first
> service
> > due on 2011-12-27, then one on 2012-3-27, then on 2012-6-27.
> >
> > How do i go about it?
> >
> > Any help is much appreciated.
> >
> > Thanks,
>
>

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