Could it have come down to a simple typo. Checking the table name, do you have a table with the name "memeber" or "member"?
On 10 April 2012 02:20, Gavin <gavin.chalkley@xxxxxxxxx> wrote:
Hi Suman,
Yes the variables are containing data. vcode is randomly generated, loginName, and email come in from a form.
I have used var_dump, and also print on the variables, and data is there.
Best Regards, Gavin Chalkley![MSTC WES7]()
On 09/04/2012 17:14, madavapeddi suman wrote:hi,Trying seeing whether $vcode ,$loginName and $email variables contains the values?/Suman
On Mon, Apr 9, 2012 at 11:44 AM, Gavin <gavin.chalkley@xxxxxxxxx> wrote:
All,
I am having a small issue which is making me bang my head against a wall.
I am running XAMMP with PHP 5.4 installed and this worked before uploading to my live dev site.
The part of the function that doesn't seem to be working is :
$pdo = $this->connection();
$sql = "UPDATE `memeber` SET `vcode`=:vcode WHERE `loginName`=:loginName and `email`=:email";
$q = $pdo->prepare($sql);
$q->execute(array(':vcode' => $vcode, ':loginName' => $loginName, ':email' => $email));
I have tried the SQL statement direct into PHPMyAdmin, replacing the :name holders with true data, and it worked.
But trying the above script fails to update. Am i missing something completely here?
--
Best Regards, Gavin Chalkley![MSTC WES7]()
