David wrote: > > Oliver Kennedy wrote: > > ... > > I have a very simple database consisting of 1 table, I want users here > to > > be able to use a search function to query the database in order to > return > > the information on a client by a specific ID number if it is in the > > database. > > ... > > Try > > $query = "SELECT * FROM clients WHERE clientid = '$term'"; > echo $query . '<br />'; > $result = mysql_query($query); > > And see what is actually in the query. > > Cheers > -- > David Robley As David stated, output the query and copy it into the MySQL console, see if that gives you an error. You are talking about using an ID -number-, in that case using single quotes around your $term variable is incorrect but won't cause an error on MySQL servers. Especially because you are new to PHP, I would recommend to do some reading about making PHP secure, your code above has lots of possibilies for code injection and SQL injection: * Escaping variables for use in MySQL queries [1] * SQL Injection [2] * PHP and security [3] Best regards, Sascha [1] http://de.php.net/mysql_real_escape_string [2] http://de.php.net/manual/en/security.database.sql-injection.php [3] http://de.php.net/manual/en/security.php -- Freundliche GrÃÃe / Kind regards, Sascha Meyer -------------------------------------------------- EE: http://www.experts-exchange.com/M_761556.html ZCE: http://www.zend.com/en/yellow-pages#show-ClientCandidateID=ZEND011290 GRATIS! Movie-FLAT mit Ãber 300 Videos. Jetzt freischalten unter http://portal.gmx.net/de/go/maxdome -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
