Thanks.
Figured it out, and also know shouldn't just copy and paste too much code as
such...<smile>
Stay well
Jacob Kruger
Blind Biker
Skype: BlindZA
'...fate had broken his body, but not his spirit...'
----- Original Message -----
From: "Toby Hart Dyke" <toby@xxxxxxxxxxxx>
To: "Jacob Kruger" <jacobk@xxxxxxxxxxxxxx>
Cc: <php-windows@xxxxxxxxxxxxx>
Sent: Tuesday, April 13, 2010 12:00 PM
Subject: Re: Trouble running a select query against a database,
when I know the connection is working, and the data is there
On 4/13/2010 9:36 AM, Jacob Kruger wrote:
$qry = mysql_query($sql);
$arr = mysql_fetch_array($qry);
if ($arr.count > 0)
{
echo "<ul>";
while($row = mysql_fetch_array($arr))
You retrieve a row, check if it has any elements, then attempt to retrieve
the next row, using the array you just created as the argument. You should
be using $qry as the argument, but you're skipping over the first row.
Toby
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__________ Information from ESET NOD32 Antivirus, version of virus signature database 5026 (20100413) __________
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