You could also do:
$daystosubtract = 3;
$mydate =
(date("m/d/y",mktime(0,0,0,date("m"),date("d")-$daystosubtract,date("Y"))));
Jeremy Schreckhise
"Jason Barnett" <jason.barnett@xxxxxxxxxxxxx> wrote in message
news:20050131172952.61088.qmail@xxxxxxxxxxxxxxxx
> Ron Herhuth wrote:
> > I am trying to construct a function where I feed it a number such as "x"
> > it returns the date "x" days ago.
>
> <?php
>
> $format = 'l dS of F Y h:i:s A';
>
> /** Check that "now" relative time is ok, instead of midnight */
> echo date($format, strtotime("now")) . "\n";
>
> /** If now resolves correctly, then this should work */
> $x = strtotime("-1 days");
> echo date($format, $x);
>
> ?>
>
> >
> > I tried checking out several resources that give you the difference
> > between two dates, but not exactly what I was looking for. I was just
> > hoping someone had a little algorithm in their bag of tricks.
> >
> > Thanks,
> > Ron
> >
>
>
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