Greetings,
I am running MS Word under wine.
>From an MS Word macro, I can easily translate a Linux path to a
'Windows' path using GetFullPathName() -- code below.
My question is how best to do the opposite -- not necessarily from a
'Windows' program.
Ex., given a path such as 'C:\PRETEST\GEM01494\GEM01494.RTF',
how do I get
'/home/justin/.cxoffice/dotwine/fake_windows/pretest/GEM01494/GEM01494.rtf'?
I currently have a 'solution' using a lookup table
{
'C:': '/home/justin/.cxoffice/dotwine/fake_windows',
'Y:': '/home/justin',
'Z:': '/',
}
and recursively case-insensitively comparing each remaining part of
the path with the folder contents.
My 'solution', however, breaks down when given a path such as
ex., 'C:\PROG~FBU\MICR~HFZ\TEMP~JWQ\MEMOS\Professional Memo.dot'
where the linux path for this is
'/home/justin/.cxoffice/dotwine/fake_windows/Program Files/Microsoft
Office/Templates/Memos/Professional Memo.dot'
as 'PROG~FBU' does not match 'Program Files'
<CODE>
Option Explicit
Private Declare Function GetFullPathName Lib "kernel32" _
Alias "GetFullPathNameA" (ByVal lpFileName As String, _
ByVal nBufferLength As Long, ByVal lpBuffer As String, _
ByVal lpFilePart As String) As Long
Sub test()
Dim buff As String
Dim ret As Long
Dim pth As String
pth = "/home/justin/.cxoffice/dotwine/fake_windows/pretest/GEM01494/GEM01494.rtf"
buff = Space$(1024)
ret = GetFullPathName(pth, 1024, buff, "")
buff = Left$(buff, ret)
Debug.Print ">>>" & buff & "<<<"
End Sub
</CODE>
<OUTPUT>
>>>C:\PRETEST\GEM01494\GEM01494.RTF<<<
</OUTPUT>
<MACHINE>
Mandrakelinux 10.0
Wine 20040213
Microsoft Word 97
</MACHINE>
Thank you.
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