Re: Still no luck on command line parse

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On Thu, 31 Jan 2002, Bill Medland wrote:

> I have a little test program that I threw together for investigating the
> DrawTextEx function.  (You can find it in the patches but Alexandre hasn't
> accepted it yet).  It takes input from the szCommandLine passed to WinMain.
> Under windows I can pass a set of arguments, including a string enclosed in
> quotes.  I use those quotes to recognise which part of szCommandLine is "the
> string".  (Yes, I know it's lazy and bad argument processing).  However
> under Wine the quotes don't get through and if I escape them with \ then the
> \ goes through too (which messes up "the string").  I haven't looked yet but
> there is something weird in there.  I guess one problem is that the quotes
> will be removed by the shell before even reaching Wine.
>
> Bill
>
True.  If wine sees the effect of a quote the shell has removed (spaces
in an argument), it will quote the string with \", because if it
doesn't, the C runtime will parse the spaces:

[whit@giftie cmdl]$ wine cmdl.exe "quoted string"
arg 0: /cmdl.exe/
arg 1: /quoted string/
[whit@giftie cmdl]$ wine cmdl.exe \"quoted string\"
arg 0: /cmdl.exe/
arg 1: /"quoted/
arg 2: /string"/
[whit@giftie cmdl]$ wine --dll msvcrt=n cmdl.exe "quoted string"
arg 0: /cmdl.exe/
arg 1: /quoted string/
[whit@giftie cmdl]$ wine --dll msvcrt=n cmdl.exe \"quoted string\"
arg 0: /cmdl.exe/
arg 1: /"quoted/
arg 2: /string"/
[whit@giftie cmdl]$

I know, in my example, it is actually the unix shell that is breaking
the argument in half, but I am confident the windows C runtime startup
routines do the same.  Unlike the unix shell, they only preserve spaces
in an argument quoted by \", and treat " as an ordinary character.
Just follow the URL earlier in this thread.  It is where I got the
program I compiled with lcc-win as cmdl.exe:

#include <stdio.h>
main(int argc, char **argv)
{
    int i;
    for (i = 0; i < argc; i++)
        printf("arg %d: /%s/\n", i, argv[i]);
}

Lawson


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