Hi Anatoly,
On Sat, Aug 25, 2018 at 12:36:54PM +0300, Anatoly Pugachev wrote:
Hello!
virt-what$ git desc
v1.18-6-gd7fd8a7
Latest commit in git "Allow using sysctl, for example when /proc isn't
available"
doesn't look good for me. Can someone please review/revert this commit
or explain me what does this code do (git show -1):
What this is meant to achieve, is that use_sysctl would return true
(a 0 exit code) if the OS is OpenBSD. Might be clearer if it added a
line like 'return $?' after the [..], but it is unnecessary.
+use_sysctl() {
+ # Lacking /proc, on some systems sysctl can be used instead.
+ OS=$(uname) || fail "failed to get operating system name"
+
+ [ "$OS" == "OpenBSD" ]
+}
Running on a linux:
virt-what# PATH=$PATH:. ./virt-what
./virt-what: 45: [: Linux: unexpected operator
The test operator should be seeing something like:
[ "Linux" == "OpenBSD" ]
but the error you're seeing looks more like what happens if a shell
interprets it differently - or at least is getting something else,
like the following:
[ somethingelse Linux == "OpenBSD" ]
which will give an error like you're seeing above in some shells
(not all), where it is interpreting the 'Linux' as an operator, and
is similar to:
/bin/test somethingelse Linux == "OpenBSD"
where the shell doesn't have an internal implementation of '[', like
some older bourne shell versions.
But, even if uname outputs more than one word, it should be
contained by the quotes in "$OS" in the test code above - on
whatever shell you're using that doesn't appear to be the case.
You might get more of an idea of what is happening by running the
shellscript with the -x option, e.g.
virt-what# PATH=$PATH:. /bin/sh -x ./virt-what
Thanks,
Darren.
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