Hi, using sfdisk -l I had this output: Disk /dev/sda: 19457 cylinders, 255 heads, 63 sectors/track Units = cylinders of 8225280 bytes, blocks of 1024 bytes, counting from 0 Device Boot Start End #cyls #blocks Id System /dev/sda1 * 0+ 3038 3039- 24410736 7 HPFS/NTFS/exFAT /dev/sda2 18936+ 19456- 521- 4180680 12 Compaq diagnostics /dev/sda3 3039 5390 2352 18892440 83 Linux /dev/sda4 5391 18935 13545 108800212+ 5 Extended /dev/sda5 9725+ 12764 3040- 24418768+ 7 HPFS/NTFS/exFAT /dev/sda6 12765+ 18935 6171- 49568526 7 HPFS/NTFS/exFAT Disk /dev/sdb: 10337 cylinders, 240 heads, 63 sectors/track Units = cylinders of 7741440 bytes, blocks of 1024 bytes, counting from 0 Device Boot Start End #cyls #blocks Id System /dev/sdb1 * 0+ 4604- 4605- 34812823+ 7 HPFS/NTFS/exFAT /dev/sdb2 9782 10336 555 4195800 12 Compaq diagnostics /dev/sdb3 5952 9781 3830 28954800 f W95 Ext'd (LBA) /dev/sdb4 4604+ 5951- 1348- 10183680 7 HPFS/NTFS/exFAT /dev/sdb5 5952+ 9781 3830- 28954768+ b W95 FAT32 So I'm wondering why sfdisk assumed sdb to be 240 head-aligned instead of 255. All partitions except the sdb2 match with the 255*63 alignment. Any hint, how the geometry should be estimated correctly? Many thanks to your answer, -Ulf -- To unsubscribe from this list: send the line "unsubscribe util-linux" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
