[PATCH] MIPS: relocate_code: fix relocation area size

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relocate_code() calculates relocation area size as a sum (barebox_image_size +
bss_len). barebox_image_size and bss_len are calculated as (__image_end -
__image_start) and (__bss_stop - __bss_start) respectively. This doesn't take
into account relocation data placed between  __image_end and __bss_start.
However relocation preserves BSS position relative to image start, as if
relocation data is still there. This causes RAM overflow during BSS
initialization in main_entry(). This problem may be hidden due to the alignment
of the `relocaddr`.

Signed-off-by: Peter Mamonov <pmamonov@xxxxxxxxx>
---
 arch/mips/lib/reloc.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/arch/mips/lib/reloc.c b/arch/mips/lib/reloc.c
index 32d776a6a6..41e2d5c75f 100644
--- a/arch/mips/lib/reloc.c
+++ b/arch/mips/lib/reloc.c
@@ -121,7 +121,7 @@ void relocate_code(void *fdt, u32 fdt_size, u32 ram_size)
 	memset(__bss_start, 0, bss_len);
 	cpu_probe();
 
-	length = barebox_image_size + bss_len;
+	length = __bss_stop - __image_start;
 	relocaddr = ALIGN_DOWN(ram_size - length, SZ_64K);
 	relocaddr = KSEG0ADDR(relocaddr);
 	new_stack = relocaddr - MALLOC_SIZE - 16;
-- 
2.24.0


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